TSTP Solution File: NUM699^1 by cocATP---0.2.0
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%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : NUM699^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n087.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.625MB
% OS : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan 8 13:11:29 EST 2018
% Result : Theorem 0.39s
% Output : Proof 0.39s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.04 % Problem : NUM699^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.24 % Computer : n087.star.cs.uiowa.edu
% 0.02/0.24 % Model : x86_64 x86_64
% 0.02/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.24 % Memory : 32218.625MB
% 0.02/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.24 % CPULimit : 300
% 0.02/0.24 % DateTime : Fri Jan 5 13:05:34 CST 2018
% 0.02/0.24 % CPUTime :
% 0.02/0.25 Python 2.7.13
% 0.39/0.58 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.Type object at 0x2b2f40130680>) of role type named nat_type
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring nat:Type
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130200>, <kernel.Constant object at 0x2b2f40130368>) of role type named x
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring x:nat
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f3889f680>, <kernel.Constant object at 0x2b2f40130368>) of role type named y
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring y:nat
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.DependentProduct object at 0x2b2f40140fc8>) of role type named less
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring less:(nat->(nat->Prop))
% 0.39/0.58 FOF formula ((less y) x) of role axiom named l
% 0.39/0.58 A new axiom: ((less y) x)
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130050>, <kernel.DependentProduct object at 0x2b2f40140c20>) of role type named lessis
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring lessis:(nat->(nat->Prop))
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130200>, <kernel.DependentProduct object at 0x2b2f40140e18>) of role type named suc
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring suc:(nat->nat)
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130368>, <kernel.DependentProduct object at 0x2b2f40140950>) of role type named pl
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring pl:(nat->(nat->nat))
% 0.39/0.58 FOF formula (<kernel.Constant object at 0x2b2f40130368>, <kernel.Constant object at 0x2b2f40140950>) of role type named n_1
% 0.39/0.58 Using role type
% 0.39/0.58 Declaring n_1:nat
% 0.39/0.58 FOF formula (forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx))) of role axiom named satz25b
% 0.39/0.58 A new axiom: (forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx)))
% 0.39/0.58 FOF formula (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) of role axiom named satz4a
% 0.39/0.58 A new axiom: (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx)))
% 0.39/0.58 FOF formula ((lessis (suc y)) x) of role conjecture named satz25c
% 0.39/0.58 Conjecture to prove = ((lessis (suc y)) x):Prop
% 0.39/0.58 We need to prove ['((lessis (suc y)) x)']
% 0.39/0.58 Parameter nat:Type.
% 0.39/0.58 Parameter x:nat.
% 0.39/0.58 Parameter y:nat.
% 0.39/0.58 Parameter less:(nat->(nat->Prop)).
% 0.39/0.58 Axiom l:((less y) x).
% 0.39/0.58 Parameter lessis:(nat->(nat->Prop)).
% 0.39/0.58 Parameter suc:(nat->nat).
% 0.39/0.58 Parameter pl:(nat->(nat->nat)).
% 0.39/0.58 Parameter n_1:nat.
% 0.39/0.58 Axiom satz25b:(forall (Xx:nat) (Xy:nat), (((less Xy) Xx)->((lessis ((pl Xy) n_1)) Xx))).
% 0.39/0.58 Axiom satz4a:(forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))).
% 0.39/0.58 Trying to prove ((lessis (suc y)) x)
% 0.39/0.58 Found l:((less y) x)
% 0.39/0.58 Found l as proof of ((less y) x)
% 0.39/0.58 Found (satz25b00 l) as proof of ((lessis ((pl y) n_1)) x)
% 0.39/0.58 Found ((satz25b0 y) l) as proof of ((lessis ((pl y) n_1)) x)
% 0.39/0.58 Found (((satz25b x) y) l) as proof of ((lessis ((pl y) n_1)) x)
% 0.39/0.58 Found (((satz25b x) y) l) as proof of ((lessis ((pl y) n_1)) x)
% 0.39/0.58 Found (satz4a00 (((satz25b x) y) l)) as proof of ((lessis (suc y)) x)
% 0.39/0.58 Found ((satz4a0 (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x)
% 0.39/0.58 Found (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x)
% 0.39/0.58 Found (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l)) as proof of ((lessis (suc y)) x)
% 0.39/0.58 Got proof (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l))
% 0.39/0.58 Time elapsed = 0.047525s
% 0.39/0.58 node=14 cost=108.000000 depth=8
% 0.39/0.58::::::::::::::::::::::
% 0.39/0.58 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.58 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.58 (((satz4a y) (fun (x1:nat)=> ((lessis x1) x))) (((satz25b x) y) l))
% 0.39/0.58 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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